ashleymnoon19owbvfv ashleymnoon19owbvfv
  • 04-03-2018
  • Mathematics
contestada

So I tried to answer this the best that I can but I keep getting wrong answers can someone help me I will award brainliest .

So I tried to answer this the best that I can but I keep getting wrong answers can someone help me I will award brainliest class=

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caylus
caylus caylus
  • 04-03-2018
Hello,

[tex]2*\sqrt{3}*\dfrac{cos(x)}{sin(x)}+4*cos(x)- \dfrac{3}{sin(x)} +2*\sqrt{3}\\ =2*cos(x)*(\dfrac{\sqrt{3}}{sin(x)}+2)-\sqrt{3}(\dfrac{\sqrt{3}}{sin(x)}+2)\\ =(\dfrac{\sqrt{3}}{sin(x)}+2)*(2*cos(x)-\sqrt{3})\\\\ cos(x)=\dfrac{\sqrt{3}}{2} -\ \textgreater \ x=\dfrac{\pi}{6}\ or\ x=\dfrac{11*\pi}{6}\\ or\\ \dfrac{\sqrt{3}}{sin(x)}+2=0-\ \textgreater \ sin(x)=-\dfrac{\sqrt{3}}{2}-\ \textgreater \ x=\dfrac{5*\pi}{3}\ or\ x=\dfrac{4*\pi}{3}\\\\ [/tex]

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