jasminemorin4 jasminemorin4
  • 01-04-2018
  • Mathematics
contestada

Which of the following equations has only one solution?
x2 - 8x + 16 = 0 x(x - 1) = 8 x2 = 16

Respuesta :

aencabo
aencabo aencabo
  • 01-04-2018
If your choices are the following:
A. x2 - 8x + 16 = 0
B. x(x - 1) = 8
C. x2 = 16

The answer is letter A. The linear equation, x2 - 8x + 16 = 0, will give you one solution only.
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11beehshahbaz 11beehshahbaz
  • 01-04-2018
Correct Answer is: [tex] x^{2} -8x+16=0[/tex]

The expression can be written as a perfect square, resulting in only 1 solution as shown below:

[tex] x^{2} -2(x)(4)+(4)^{2} \\ \\ (x-4)^{2}=0 \\ \\ x-4=0 \\ \\ x=4 [/tex]

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