hackingfaceboop6jm55 hackingfaceboop6jm55
  • 02-04-2018
  • Physics
contestada

Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds

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sdgismep6d4p4
sdgismep6d4p4 sdgismep6d4p4
  • 02-04-2018
Acceleration is equivalent to the rate of change of velocity.

Calculate the difference of velocity, and divide by the total time it took for the change to happen.

[tex](33 \frac{m}{s} - 11 \frac{m}{s} ) \div 10seconds \\ = 2 \frac{m}{ {s}^{2} } [/tex]
That is the answer.
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zaidkamalkhan12
zaidkamalkhan12 zaidkamalkhan12
  • 02-04-2018
as we know that 
a= dell   V/t
then put values
a=   2ms/^2
Answer Link

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